JAVA Threads
What is the output for the below code ?class A implements Runnable{ public void run(){ System.out.println(Thread.currentThread().getName()); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.setName("good");6. t.start();7. }8. }

Compilation fails with an error at line 5
Compilation succeed but Runtime Exception
null
None of these
good

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JAVA Threads
What will be the output of the following program code?public class Test implements Runnable{ public static void main(String[] args){ Thread t = new Thread(this); t.start(); } public void run(){ System.out.println("test"); }}

None of these
The program compiles fine, but it does not print anything because t does not invoke the run() method
The program compiles and runs fine and displays test on the console.
The program does not compile because this cannot be referenced in a static method.

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JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); t.start(); } public void run() { }}

The program does not compile because the start() method is not defined in the Test class.
The program compiles and runs fine.
The program compiles, but it does not run because the run() method is not implemented.
The program compiles, but it does not run because the start() method is not defined.

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A B A B A B A B
Output order is not guaranteed
Compilation succeed but Runtime Exception
None of these
A A A A B B B B

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