C Programming What does the following declaration mean?int (*ptr)[10]; ptr is a pointer to an array of 10 integers ptr is array of pointers to 10 integers ptr is an array of 10 integers ptr is an pointer to array ptr is a pointer to an array of 10 integers ptr is array of pointers to 10 integers ptr is an array of 10 integers ptr is an pointer to array ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ptr is a pointer to integer, p is not. ptr and p, both are pointers to integer. ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ptr is a pointer to integer, p is not. ptr and p, both are pointers to integer. ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the following program code?main(){ static int var = 5; printf("%d ", var--); if(var) main();} 5 4 3 2 1 Compilation Error None of these Infinite Loop 5 5 5 5 5 5 4 3 2 1 Compilation Error None of these Infinite Loop 5 5 5 5 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming short testarray[4][3] = { {1}, {2,3}, {4,5,6}};printf("%d", sizeof(testarray));Assuming a short is two bytes long, what will be printed by the above code? 7 12 24 It will not compile because not enough initializers are given 6 7 12 24 It will not compile because not enough initializers are given 6 ANSWER DOWNLOAD EXAMIANS APP
C Programming Find the output of the following program.void main(){ char *msg = "hi"; printf(msg);} Garbage Value h Error hi hi followed by garbage value Garbage Value h Error hi hi followed by garbage value ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the right choice, if the following loop is implemented?void main(){ int num = 0; do{ --num; printf("%d", num); }while( ++num >= 0 );} A run time error will be generated. There will be a compilation error reported. The program will not enter into the loop. The loop will run infinitely many times. Prints the value of 0 one time only. A run time error will be generated. There will be a compilation error reported. The program will not enter into the loop. The loop will run infinitely many times. Prints the value of 0 one time only. ANSWER DOWNLOAD EXAMIANS APP
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