Engineering Thermodynamics The sum of internal energy (U) and the product of pressure and volume (p.v) is known as Enthalpy Work done Power Entropy Enthalpy Work done Power Entropy ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics When gas is heated at constant pressure, the heat supplied is utilized in Increasing the internal energy of gas and also for doing some external work None of these Doing some external work Increasing the internal energy of gas Increasing the internal energy of gas and also for doing some external work None of these Doing some external work Increasing the internal energy of gas ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is 29.27 kgfm/mol °K 848 kgfm/mol °K 8314 kgfm/mol °K 427 kgfm/mol °K 29.27 kgfm/mol °K 848 kgfm/mol °K 8314 kgfm/mol °K 427 kgfm/mol °K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Which of the following process can be made reversible with the help of a regenerator? Constant volume process All of these Constant pressure process Constant pvn process Constant volume process All of these Constant pressure process Constant pvn process ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The specific heat at constant volume is Any one of the above The amount of heat required to raise the temperature of unit mass of gas through one degree, at constant volume The amount of heat required to raise the temperature of 1 kg of water through one degree The amount of heat required to raise the temperature of unit mass of gas through one degree, at constant pressure Any one of the above The amount of heat required to raise the temperature of unit mass of gas through one degree, at constant volume The amount of heat required to raise the temperature of 1 kg of water through one degree The amount of heat required to raise the temperature of unit mass of gas through one degree, at constant pressure ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) δQ = T/ds None of the listed here dQ = ds/T δQ = T.ds δQ = T/ds None of the listed here dQ = ds/T δQ = T.ds ANSWER DOWNLOAD EXAMIANS APP
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