Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ P² + Q² + 2PQ cos θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For a simple pendulum, time period for a beat, is π √(l/g) π √(g/2l) π √(2l/g) π √(l/2g) π √(l/g) π √(g/2l) π √(2l/g) π √(l/2g) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The number of funicular polygons which can be drawn to pass through two specified points in the space diagram are 2 infinity 1 zero 2 infinity 1 zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A Seconds pendulum executes 1.0 beat per second 2.0 beats per second 2.5 beats per second 0.5 beat per second 1.0 beat per second 2.0 beats per second 2.5 beats per second 0.5 beat per second ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the given forces P₁, P₂, P₃ and P₄ are such that the force polygon does not close, then the system will Always reduce to a resultant force Be in equilibrium Always reduce to a couple Both (A) and (C) Always reduce to a resultant force Be in equilibrium Always reduce to a couple Both (A) and (C) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The ratio of kinetic energy and potential energy of a simple harmonic oscillator, at a displacement equal to half its amplitude is given by 0.042361111111111 0.043055555555556 0.084027777777778 0.12569444444444 0.042361111111111 0.043055555555556 0.084027777777778 0.12569444444444 ANSWER DOWNLOAD EXAMIANS APP
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