Engineering Mechanics The resolved part of the resultant of two forces inclined at an angle 'θ' in a given direction is equal to The sum of the resolved parts of the forces in the given direction The algebraic sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the forces multiplied by the sine of θ The sum of the resolved parts of the forces in the given direction The algebraic sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the forces multiplied by the sine of θ ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Coplanar concurrent forces are those forces which Do not meet at one point and their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Meet at one point and their lines of action also lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Meet at one point and their lines of action also lie on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A smooth cylinder lying on a __________ is in neutral equilibrium. Horizontal surface Convex surface Curved surface None of these Horizontal surface Convex surface Curved surface None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as -8.9 m/s2 -9.8 m/s2 +9.8 m/s2 +8.9 m/s2 -8.9 m/s2 -9.8 m/s2 +9.8 m/s2 +8.9 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a person, on a bicycle, drives round a curve, he has to lean __________ to maintain equilibrium. Towards front Towards back Outward Inward Towards front Towards back Outward Inward ANSWER DOWNLOAD EXAMIANS APP
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