Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design The stretching in a belt can be controlled by __________ the stress in the belt. Increasing None of these Reducing Both A and B Increasing None of these Reducing Both A and B ANSWER DOWNLOAD EXAMIANS APP
Machine Design A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where σ = Stress for a plate with no hole i.e. nominal stress) σ [1 + (b/2a)] σ [1 + (b/3a)] σ [1 + (3a/b)] σ [1 + (2a/b)] σ [1 + (b/2a)] σ [1 + (b/3a)] σ [1 + (3a/b)] σ [1 + (2a/b)] ANSWER DOWNLOAD EXAMIANS APP
Machine Design In levers, leverage is the ratio of Load lifted to the effort applied Effort arm to the load arm Mechanical advantage to the velocity ratio Load arm to the effort arm Load lifted to the effort applied Effort arm to the load arm Mechanical advantage to the velocity ratio Load arm to the effort arm ANSWER DOWNLOAD EXAMIANS APP
Machine Design The permissible stress in the fillet weld is 100 N/mm². The fillet weld has equal leg lengths of 15 mm each. The allowable shearing load on the weldment per cm length of the weld is 7.5 kN 15 kN 22.5 kN 10.6 kN 7.5 kN 15 kN 22.5 kN 10.6 kN ANSWER DOWNLOAD EXAMIANS APP
Machine Design Fibrous fracture occurs in Elastic material Ductile material Brittle material Hard material Elastic material Ductile material Brittle material Hard material ANSWER DOWNLOAD EXAMIANS APP
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