SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

4A
2A
120A
12A

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SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

dΦ ⁄ dA
dA ⁄ dΦ
Φ × A
dΦ − dA

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SSC JE Electrical 2019 with solution SET-1
 In an AC network, the load connected is (10 + j10). The phase relation between the voltage applied and the current through the load is:

Voltage leads current by 45°
Voltage lags current by 45°
Voltage lags current by 30°
Voltage and current are in phase with each other

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