Engineering Mechanics The power developed by a body acted upon by a torque 'T' Newton meter (N - m) and revolving at ω radian/s is given by T.ω/4500 (in kilowatts) T.ω (in watts) T.ω/60 (in watts) T.ω/75 (in kilowatts) T.ω/4500 (in kilowatts) T.ω (in watts) T.ω/60 (in watts) T.ω/75 (in kilowatts) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to completely specify angular displacement by a vector, it must fix All of these Direction of the axis of rotation Sense of angular displacement Magnitude of angular displacement All of these Direction of the axis of rotation Sense of angular displacement Magnitude of angular displacement ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum frictional force which comes into play when a body just begins to slide over another surface is called Kinematic friction Rolling friction Limiting friction Sliding friction Kinematic friction Rolling friction Limiting friction Sliding friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear acceleration (a) of a body rotating along a circular path of radius (r) with an angular acceleration of α rad/s2, is a = r / α None of these a = α.r a = α/ r a = r / α None of these a = α.r a = α/ r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lift the load is given by (where W = Load lifted, α = Helix angle, and φ = Angle of friction.) P = W tan (φ - α) P = W tan (α + φ) P = W cos (α + φ) P = W tan (α - φ) P = W tan (φ - α) P = W tan (α + φ) P = W cos (α + φ) P = W tan (α - φ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
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