Lap Winding:-In a lap winding the number of parallel paths (a) is always equal to the number of poles (p) and also to the number of brushes. In the given question number of poles is 4 hence the number of brushes will be 4. Wave Winding:- In wave windings, the number of parallel paths (a) is always two and there may be two or more brush positions.
Io = V/R = 20/100 Io = 0.2 A Since the given diode is an ideal diode therefore there is no voltage drop across it. Vo = Io × RD Vo = 0.2 × 0 Vo = 0 Hence Io = 0.2 A & Vo = 0
Atoms or ions with unpaired electrons are attracted to a magnetic field; the more unpaired electrons, the greater is the attraction. Such substances are called paramagnetic. Molecular oxygen is a paramagnetic gas by virtue of its two unpaired electrons.
In nuclear power plant the graphite is used as a moderator. The job of the moderator is to absorb some of the kinetic energy of the neutrons to slow them down. This is because slow neutrons are more easily absorbed by uranium-235. A neutron slowed In this way can start the fission process.
The strength of a magnetic field is specified by the magnetic induction B or by the magnetic field strength H. A current I through a long, straight wire produces a magnetic field with strength H = I/2πr at a distance r from the wire. Given H = 1 A/m I = 10 A H = I/2πr 1 = 10/2πr r = 10/2π
No of disc required for 11 kV transmission line = 1 disc Since the transmission line is 3-phase, therefore, the number of discs required for a single-pole will be 3. Total no. of poles = 80 No of disc = 3 × 80 = 240
EXAMIANS