Electric Circuits The norton equivalent of the circuit shown in the figure is 0.75 A, 1.5 Ohm 0.75A, 5/6 Ohm 1A, 1.5 Ohm 1A, 5/6 Ohm 0.75 A, 1.5 Ohm 0.75A, 5/6 Ohm 1A, 1.5 Ohm 1A, 5/6 Ohm ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Electric field intensity ( E ) at any point in an electric field is equal to potential gradient. ( potential gradient )1/2. ( potential gradient )2. ( potential gradient )1/3. potential gradient. ( potential gradient )1/2. ( potential gradient )2. ( potential gradient )1/3. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The unit of electric displacement vector is C/m2. C - m. Ampere-m. C/m. C/m2. C - m. Ampere-m. C/m. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits If a pure inductor is connected across the ac source, the average power taken by the inductor is 100 watt. a few watt. maximum power. zero watt. 100 watt. a few watt. maximum power. zero watt. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Two battery having unequal emf cannot be connected in series. both a and d can be connected in series only. cannot be connected in parallel. cannot be connected in series. both a and d can be connected in series only. cannot be connected in parallel. ANSWER DOWNLOAD EXAMIANS APP
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