Applied Mechanics and Graphic Statics The maximum displacement of a particle executing S.H.M. corresponds to Zero potential energy and maximum kinetic energy Zero kinetic energy and maximum potential energy Maximum kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy Zero potential energy and maximum kinetic energy Zero kinetic energy and maximum potential energy Maximum kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A vehicle weighing w kg is to run on a circular curve of radius r. If the height of its centre of gravity above the road level is h and the distance between the centres of wheels is 2a, the maximum velocity, in order to avoid over turning, will be ∛(gra/h) 4√(gra/h) gra/h √(gra/h) ∛(gra/h) 4√(gra/h) gra/h √(gra/h) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time period and length of a second’s pendulum respectively are 1 sec and 99.4 cm 2 sec and 99.4 cm 2 sec and 92.7 cm 1 sec and 92.7 cm 1 sec and 99.4 cm 2 sec and 99.4 cm 2 sec and 92.7 cm 1 sec and 92.7 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two objects moving with uniform speeds are 5 m apart after 1 second when they move towards each other and are 1 m apart when they move in the same direction.The speeds of the objects are: 2 m/sec and 2 m/sec 3 m/sec and 3 m/sec 4 m/sec and 6 m/sec 3 m/sec and 2 m/sec 2 m/sec and 2 m/sec 3 m/sec and 3 m/sec 4 m/sec and 6 m/sec 3 m/sec and 2 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be 200 tonnes at the centre 500 tonnes at the centre 200 tonnes at the right support 200 tonnes at the left support 200 tonnes at the centre 500 tonnes at the centre 200 tonnes at the right support 200 tonnes at the left support ANSWER DOWNLOAD EXAMIANS APP
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