Engineering Thermodynamics The main cause for the irreversibility is Mechanical and fluid friction All of these Heat transfer with a finite temperature difference Unrestricted expansion Mechanical and fluid friction All of these Heat transfer with a finite temperature difference Unrestricted expansion ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The volumetric or molar specific heat at constant pressure is the product of Molecular mass of the gas and the specific heat at constant volume Molecular mass of the gas and the gas constant Atomic mass of the gas and the gas constant None of the listed here Molecular mass of the gas and the specific heat at constant volume Molecular mass of the gas and the gas constant Atomic mass of the gas and the gas constant None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Specific heat of air at constant pressure is equal to 0.17 1 0.21 0.24 0.17 1 0.21 0.24 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits? SO₂, NH₃, CO₂, moisture O₂, N₂, steam, CO₂ O₂, N₂, water vapour O₂, N₂, H₂, air SO₂, NH₃, CO₂, moisture O₂, N₂, steam, CO₂ O₂, N₂, water vapour O₂, N₂, H₂, air ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Characteristic gas constant of a gas is equal to Cv /Cp Cp /Cv Cp - Cv Cp + Cv Cv /Cp Cp /Cv Cp - Cv Cp + Cv ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics If a system after undergoing a series of processes, returns to the initial state then Its entropy will change due to irreversibility Process is executed in closed system cycle Sum of heat and work transfer will be zero Process is thermodynamically in equilibrium Its entropy will change due to irreversibility Process is executed in closed system cycle Sum of heat and work transfer will be zero Process is thermodynamically in equilibrium ANSWER DOWNLOAD EXAMIANS APP
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