MGVCL Exam Paper (30-07-2021 Shift 3) The magnetizing inrush current in a transformer is rich in the harmonic component. third second fifth seventh third second fifth seventh ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2nd harmonics contains - 60 to 55 %3rd harmonics contains - 40 - 50%
MGVCL Exam Paper (30-07-2021 Shift 3) Rearrange the following to form a meaningful sentence and find the most logical order from the given options.P: globally, out of which over 200 millionQ: are now in India, andR: flipkart has 700 million usersS: growing exponentially RPSQ RSQP PQRS RPQS RPSQ RSQP PQRS RPQS ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 400 W and -50 W. Calculate the reactive power taken by the load 350/√3 VAR 450√3 VAR 450/√3 VAR 350√3 VAR 350/√3 VAR 450√3 VAR 450/√3 VAR 350√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken (Q) = √3*(W1 - W2)= √3*(450 + 50)= √3*450 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) What is the full form of the acronym 'SWIFT', in financial institution? Social Wide in Financial Transaction Society for Worldwide Interbank Financial Telecommunication Social World interconnection in Financial Tech process Society website in Financial Terms Social Wide in Financial Transaction Society for Worldwide Interbank Financial Telecommunication Social World interconnection in Financial Tech process Society website in Financial Terms ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) વિષમ' ની સંધી છૂટી પાડો. - કયો વિકલ્પ સાચો છે? વિસ્ + અમ વિ + સમ વીસ + અમ વી + સમ વિસ્ + અમ વિ + સમ વીસ + અમ વી + સમ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A conductor having surface density is embedded in a dielectric medium of permittivity. The electric field in the medium is E. If it is known that the pressure p on the conductor surface is equal to the electric energy density in the medium, then p (in SI unit)is given by σ²/(4π) σ/(4πε) σ²/(2ε) σ²/(2πε) σ²/(4π) σ/(4πε) σ²/(2ε) σ²/(2πε) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP As the point is near to the conductor will act as infinite sheetElectric field (E) is given by:E = σ²/(2ϵ)
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