Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1983 1683 1183 1383 1983 1683 1183 1383 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
Problems on H.C.F and L.C.M The greatest number of four digits that have 144 for their HCF is? 9903 9930 9935 9936 9903 9930 9935 9936 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest possible length which can be used to measure exactly the length 4 m 95 cm . , 9 m and 16 m 65 cm. 42 cm. 45 cm. 35 cm 55 cm. 42 cm. 45 cm. 35 cm 55 cm. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 630 770 540 420 630 770 540 420 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
Problems on H.C.F and L.C.M Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively 16 17 18 19 16 17 18 19 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF of (400-9, 435-10, 541-14)HCF of (391, 425, 527) = 17
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 4 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
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