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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is:

995
893
982
1024

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

308
208
408
508

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other number = (11 x 7700/275) = 308.

Problems on H.C.F and L.C.M
The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

1001
1911
91
910

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm

255 cm
275 cm
285 cm
265 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.

Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?

4
16
10
15

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2

Problems on H.C.F and L.C.M
L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is:

-2
1
2
-1

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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