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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is:

893
995
982
1024

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

2
-1
-2
1

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is:

6400
1600
3600
14400

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

875
1305
48
435

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

11340
12765
9720
10478

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

110
180
420
360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

MORE MCQ ON Problems on H.C.F and L.C.M

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