Engineering Mechanics The ideal angle of banking provided on the curves on roads depends upon Nature of the road surface Weight of the vehicle (Velocity)2 of the vehicle Coefficient of friction between the road and vehicle contact point Nature of the road surface Weight of the vehicle (Velocity)2 of the vehicle Coefficient of friction between the road and vehicle contact point ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A weight of 1000 N can be lifted by an effort of 80 N. If the velocity ratio is 20, the machine is None of these Ideal Reversible Non-reversible None of these Ideal Reversible Non-reversible ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by (where, r = Amplitude of motion, and y = Displacement of the particle from mean position.) ω².√(y² - r²) ω.√(r² - y²) ω.√(y² - r²) ω².√(r² - y²) ω².√(y² - r²) ω.√(r² - y²) ω.√(y² - r²) ω².√(r² - y²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.) P = W (cosα + μsinα) P = W tan (α + φ) P = W tanα P = W (sinα + μcosα) P = W (cosα + μsinα) P = W tan (α + φ) P = W tanα P = W (sinα + μcosα) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion is below the centre of gravity of the body and is at a distance equal to kG2/h h2/kG h × kG h/kG kG2/h h2/kG h × kG h/kG ANSWER DOWNLOAD EXAMIANS APP
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