Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is (kG² + h²)/h² h²/(kG² + h²) (kG² + h²)/h h/(kG² + h²) (kG² + h²)/h² h²/(kG² + h²) (kG² + h²)/h h/(kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum frictional force, which comes into play, when a body just begins to slide over the surface of the other body, is known as Static friction Limiting friction Dynamic friction Coefficient of friction Static friction Limiting friction Dynamic friction Coefficient of friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The ratio of static friction to dynamic friction is always None of these Greater than one Equal to one Less than one None of these Greater than one Equal to one Less than one ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of forces are acting at a point, their resultant is given by √[(∑V)2 +(∑H)2 +2(∑V)(∑H)] (∑V)2 + (∑H)2 √[(∑V)2 + (∑H)2] (∑V)2 +(∑H)2 +2(∑V)(∑H) √[(∑V)2 +(∑H)2 +2(∑V)(∑H)] (∑V)2 + (∑H)2 √[(∑V)2 + (∑H)2] (∑V)2 +(∑H)2 +2(∑V)(∑H) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to determine the effects of a force, acting on a body, we must know All of these Line of action of the force Nature of the force i.e. whether the force is push or pull Magnitude of the force All of these Line of action of the force Nature of the force i.e. whether the force is push or pull Magnitude of the force ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The algebraic sum of moments of the forces forming couple about any point in their plane is Both of above are wrong Both of above are correct Constant Equal to the moment of the couple Both of above are wrong Both of above are correct Constant Equal to the moment of the couple ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS