The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture?

• A. None of these
• B. 8
• C. 4
• D. 5

Answer: (D)

           Wine                         Water             8L                              32L             1                :               4            20 %                           80% (original ratio)            30 %                           70% (required ratio)   In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.   so the ratio of left quantity to the initial quantity is 7:8   Therefore ,  7 8 = 1 - K 40   => K = 5 Lit