Steam Boilers, Engines, Nozzles and Turbines The diameter of superheated tubes in a locomotive boiler is 13 mm 31 mm 230 mm 130 mm 13 mm 31 mm 230 mm 130 mm ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines In recuperative air preheaters, the heat is transferred From a metal wall from one medium to another From heating an intermediate material and then heating the air from this material Heat is transferred by bleeding some gases from furnace By direct mixing From a metal wall from one medium to another From heating an intermediate material and then heating the air from this material Heat is transferred by bleeding some gases from furnace By direct mixing ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Heating of dry steam above saturation temperature is known as Superheating Enthalpy Latent heat Super saturation Superheating Enthalpy Latent heat Super saturation ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Gusset stays in a boiler are provided to Support furnace freely from top Prevent the bulging of flat surfaces Avoid explosion in furnace Prevent leakage of hot flue gases Support furnace freely from top Prevent the bulging of flat surfaces Avoid explosion in furnace Prevent leakage of hot flue gases ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines The impulse turbine rotor efficiency will have a maximum value of 0.5 cos 2α, where α is the nozzle exit flow angle, if the Blades are equiangular and frictionless Blades are equiangular Blade solidity is 0.65 Blade velocity coefficient is unity Blades are equiangular and frictionless Blades are equiangular Blade solidity is 0.65 Blade velocity coefficient is unity ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines The critical pressure ratio (p₂/p₁) is given by (p₂/p₁) = [2/(n - 1)] n/(n + 1) (p₂/p₁) = [(n - 1)/2] n + (1/n) (p₂/p₁) = [(n + 1)/2] n - (1/n) (p₂/p₁) = [2/(n + 1)] n/(n-1) (p₂/p₁) = [2/(n - 1)] n/(n + 1) (p₂/p₁) = [(n - 1)/2] n + (1/n) (p₂/p₁) = [(n + 1)/2] n - (1/n) (p₂/p₁) = [2/(n + 1)] n/(n-1) ANSWER DOWNLOAD EXAMIANS APP
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