Hydraulics and Fluid Mechanics in ME The depth ‘d’ below the free surface at which the point velocity is equal to the average velocity of flow for a uniform laminar flow with a free surface, will be (where D is the depth of flow) 0.577 D 0.707 D 0.223 D 0.423 D 0.577 D 0.707 D 0.223 D 0.423 D ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A piece of metal of specific gravity 13.6 is placed in mercury of specific gravity 13.6, what fraction of it volume is under mercury? The metal piece will be immersed in mercury by half The metal piece will simply float over the mercury Whole of the metal piece will be immersed with its top surface just at mercury level Metal piece will sink to the bottom The metal piece will be immersed in mercury by half The metal piece will simply float over the mercury Whole of the metal piece will be immersed with its top surface just at mercury level Metal piece will sink to the bottom ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The power developed by a turbine is (where H = Head of water under which the turbine is working) Inversely proportional to H3/2 Directly proportional to H1/2 Directly proportional to H3/2 Inversely proportional to H1/2 Inversely proportional to H3/2 Directly proportional to H1/2 Directly proportional to H3/2 Inversely proportional to H1/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A Pelton wheel develops 1750 kW under a head of 100 meters while running at 200 r.p.m. and discharging 2500 liters of water per second. The unit speed of the wheel is 80 r.p.m. 20 r.p.m. 10 r.p.m. 40 r.p.m. 80 r.p.m. 20 r.p.m. 10 r.p.m. 40 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Metacentric height for small values of angle of heel is the distance between the free surface and centre of buoyancy centre of gravity and metacentre centre of buoyancy and metacentre centre of gravity and centre of buoy-ancy free surface and centre of buoyancy centre of gravity and metacentre centre of buoyancy and metacentre centre of gravity and centre of buoy-ancy ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2 where m is equal to 0.405 + (0.003/H) 0.003 + (H/0.405) 0.405 + (H/0.003) 0.003 + (0.405/H) 0.405 + (0.003/H) 0.003 + (H/0.405) 0.405 + (H/0.003) 0.003 + (0.405/H) ANSWER DOWNLOAD EXAMIANS APP
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