Refrigeration and Air Conditioning The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T₁ = Lowest absolute temperature, and T₂ = Highest absolute temperature) (T₁ - T₂)/T₁ T₂/ (T₂ - T₁) (T₂ - T₁)/T₁ T₁ / (T₂ - T₁) (T₁ - T₂)/T₁ T₂/ (T₂ - T₁) (T₂ - T₁)/T₁ T₁ / (T₂ - T₁) ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Moisture should be removed from refrigerants to avoid Restriction to refrigerant flow Freezing at the expansion valve Corrosion of steel plates All of these Restriction to refrigerant flow Freezing at the expansion valve Corrosion of steel plates All of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning One ton refrigeration corresponds to 80 kcal/ min 80 kcal/ hr 50 kcal/ hr 50 kcal/ min 80 kcal/ min 80 kcal/ hr 50 kcal/ hr 50 kcal/ min ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning As relative humidity decreases, the dew point temperature will be ___ wet bulb temperature. Higher than Lower than None of the listed here Same as Higher than Lower than None of the listed here Same as ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The reduced ambient air cooling system has One cooling turbine and two heat exchangers One cooling turbine and one heat exchanger Two cooling turbines and one heat exchanger Two cooling turbines and two heat exchangers One cooling turbine and two heat exchangers One cooling turbine and one heat exchanger Two cooling turbines and one heat exchanger Two cooling turbines and two heat exchangers ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning For obtaining high COP, the pressure range of compressor should be Optimum High Any value Low Optimum High Any value Low ANSWER DOWNLOAD EXAMIANS APP
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