Applied Mechanics and Graphic Statics The centre of gravity of a homogeneous body is the point at which the whole Volume of the body is assumed to be concentrated Area of the surface of the body is assumed to be concentrated All listed here Weight of the body is assumed to be concentrated Volume of the body is assumed to be concentrated Area of the surface of the body is assumed to be concentrated All listed here Weight of the body is assumed to be concentrated ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics To attain the synchronous orbit, the launch of a satellite, is done from a place On 45° latitude On the poles On 30° latitude On equator On 45° latitude On the poles On 30° latitude On equator ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is α = π/2 + β/2 α = π/4 - β/2 α = β/2 - π/2 α = π/4 - β/2 α = π/2 + β/2 α = π/4 - β/2 α = β/2 - π/2 α = π/4 - β/2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A trolley wire weighs 1 kg per metre length. The ends of the wire are attached to two poles 20 m apart. If the horizontal tension is 1000 kg, the central dip of the cable is 4 cm 2 cm 3 cm 5 cm 4 cm 2 cm 3 cm 5 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is 102.5 kg 108.5 kg 105.5 kg 110 kg 102.5 kg 108.5 kg 105.5 kg 110 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is y = ω √(y - r) v = ω √(r² + y²) v = ω √(y² - r²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(r² + y²) v = ω √(y² - r²) v = ω √(r² - y²) ANSWER DOWNLOAD EXAMIANS APP
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