Area Problems The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is? 8. 75 sq.cms 17.5 sq.cms 55 sq.cms 35 sq.cms 8. 75 sq.cms 17.5 sq.cms 55 sq.cms 35 sq.cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2
Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? 14cm 13 cm None of these 12 cm 14cm 13 cm None of these 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems If the sides of a squares is increased by 25%, then the area of the squares will be increased by 53.75% 125% 50% 56.25% 53.75% 125% 50% 56.25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%
Area Problems The Area of a square is 50 sq. units. Then the area of the circle drawn on its diagonal is? 25? sq. units None of theas 100? sq. units 50? sq. units 25? sq. units None of theas 100? sq. units 50? sq. units ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = (Diagonal)2 / 2 = 50? Diagonal = 10 units ? Radius of required circle = 5 unitsIts area = [? x (5)2 ] cm2= 25? units2
Area Problems The ratio of the area of the circumcircle and the incircle of a square is 2 : 1 ?2 : 1 1 : 2 1 : ?2 2 : 1 ?2 : 1 1 : 2 1 : ?2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
Area Problems In ? ABC ,sides BC = 10 cm and height AD = 4.4 cm. If AC = 11 cm. Then altitude BE equals? 4 cm 5 cm 5.5 cm 5.6 cm 4 cm 5 cm 5.5 cm 5.6 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We know that area of triangle = ( base x height ) / 2So area of triangle = (BC x AD) / 2 = (AC x BE) / 2 ? (10 x 4.4) / 2 = (11 x h) / 2? h= (10 x 4.4)/11 = 4 cm
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