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Area Problems

Area Problems
The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side.

9 cm
?3 cm
3?3 cm
3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm

Area Problems
The circumference of a circle is 25 cm. Find the side of the square incribed in the circle.

25/??2 cm
21/??3 cm
23/??2
29/??3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm

Area Problems
The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?

20 m
40 m
50 m
30 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x meters. Then, Length = 115x / 100 meters Given that,  X × (115X / 100) = 460 => X = 20

Area Problems
The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is?

29.46 km/hr.
36.25 km/hr.
32.72 km/hr.
31.68 km/hr.

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr

Area Problems
The Number of rounds that a wheel of diameter 7/11 m will make in going 4 km, is?

2000
1700
1000
1500

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Number of round = total distance / circumference of wheel.= (4 x 1000) / ?d= (4 x 1000) / ( 22/7 x 7/11) = 2000

Area Problems
The cost of carpeting a room 15 meters long with a carpet 75 cm wide at 30 paisa per meter is Rs. 36. The breadth of the room is?

8 meters
12 meters
6 meters
9 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length of carpet = Total Cost / Rate = 3600 / 30 = 120 mArea of carpet = (120 x 75) / 100 m2= 90 m2? Area of the room = 90 m2Breadth of the room = Area /Length = 90 / 15 m = 6m

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