Heat Transfer Steady state one dimensional heat flow by conduction as given by Fourier's low does not assume that Boundary surfaces are isothermal Material is anisotropic Constant temperature gradient exists There is no internal heat generation Boundary surfaces are isothermal Material is anisotropic Constant temperature gradient exists There is no internal heat generation ANSWER DOWNLOAD EXAMIANS APP
Heat Transfer In case of parallel flow heat exchanger, the lowest temperature theoretically attainable by the hot fluid is __________ the outlet temperature of the cold fluid. Less than More than Either more or less than (depending upon the fluid) Equal to Less than More than Either more or less than (depending upon the fluid) Equal to ANSWER DOWNLOAD EXAMIANS APP
Heat Transfer In case of __________ boiling, the bubbles formed on a submerged hot surface get absorbed in the mass of the liquid. Low pressure Nucleate Pool None of these Low pressure Nucleate Pool None of these ANSWER DOWNLOAD EXAMIANS APP
Heat Transfer Thickness of thermal boundary layer is more compared to that of hydrodynamic boundary layer, when the value of Prandtl number is 1 < 1 > 1 > 5 1 < 1 > 1 > 5 ANSWER DOWNLOAD EXAMIANS APP
Heat Transfer Finned tube heat exchangers use metal fins of low thermal conductivity are used for smaller heat load give larger area per tube facilitate very large temperature drop through tube wall use metal fins of low thermal conductivity are used for smaller heat load give larger area per tube facilitate very large temperature drop through tube wall ANSWER DOWNLOAD EXAMIANS APP
Heat Transfer The thermal efficiency of a reversible heat engine operating between two given thermal reservoirs is 0.4. The device is used either as a refrigerator or as a heat pump between the same reservoirs. Then the coefficient of performance as a refrigerator (COP)R and the co-efficient of performance as a heat pump (COP)HP are (COP)R = 1.5; (COP)HP = 2.5 (COP)R = (COP)HP = 0.6 (COP)R = (COP)HP = 2.5 (COP)R = 2.5; (COP)HP = 1.5 (COP)R = 1.5; (COP)HP = 2.5 (COP)R = (COP)HP = 0.6 (COP)R = (COP)HP = 2.5 (COP)R = 2.5; (COP)HP = 1.5 ANSWER DOWNLOAD EXAMIANS APP
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