SSC JE Electrical 2019 with solution SET-1
Reflected Light/Incident Light =

Maintenance factor
Reflection factor
Absorption factor
Waste light factor

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SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Φ × A
dΦ − dA
dA ⁄ dΦ
dΦ ⁄ dA

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
120A
12A
4A

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SSC JE Electrical 2019 with solution SET-1
 The amount of AC content present in the DC output of a rectifier is given by

Ripple factor
Peak factor
Power factor
Form factor

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