JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

Output order is not guaranteed
A B A B A B A B
Compilation succeed but Runtime Exception
None of these
A A A A B B B B

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JAVA Threads
Given the code. What will be the result?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

An exception is thrown at runtime.
"BeginRunEnd" is printed.
Compilation fails.
"BeginEnd" is printed.
"BeginEndRun" is printed.

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JAVA Threads
What will happen when you attempt to compile and run the following code?1. public class Test extends Thread{2. public static void main(String argv[]){3. Test t = new Test();4. t.run();5. t.start();6. }7. public void run(){8. System.out.println("run-test");9. }10. }

run-test
None of these
Compilation fails due to an error on line 7
Compilation fails due to an error on line 4
run-test run-test

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JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

run-a
run-a run-a
Compilation succeed but Runtime Exception
None of these
Compilation fails with an error at line 6

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