SSC JE Electrical 2019 with solution SET-2
Observe the figure and find the correct relation from the four given options?

i4 + i2 + i3 = i1 + i5 + i6
i1 + i2 + i4 = i3 + i5 + i6
i1 + i2 + i3 = i4 + i5 + i6
i1 + i2 + i6 = i4 + i5 + i3

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise ÷ Ia
IL = Ise + Ia
IL = Ise = Ia
IL ÷ Ise = Ia

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SSC JE Electrical 2019 with solution SET-2
If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the total number of sub-circuits required?

1
6
4
3

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SSC JE Electrical 2019 with solution SET-2
______braking is used where the load on the motor has very high inertia (e.g. in electric trains)?

Regenerative
Plugging
Rheostatic
Coasting

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