Hydraulics and Fluid Mechanics in ME Metacentre is the point of intersection of All of these vertical upward force through e.g. of body and center line of body buoyant force and the center line of body mid point between e.g. and center of buoyancy All of these vertical upward force through e.g. of body and center line of body buoyant force and the center line of body mid point between e.g. and center of buoyancy ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A model of a reservior is drained in 4 mts by opening the sluice gate. The model scale is 1: 225. How long should it take to empty the prototype ? 4 x V225 minutes 4 (225)1/3 minutes 4 x (225)3/2 minutes 4 minutes 4 x V225 minutes 4 (225)1/3 minutes 4 x (225)3/2 minutes 4 minutes ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Two pipe systems can be said to be equivalent, when the following quantities are same Flow and length Friction factor and diameter Friction loss and flow Length and diameter Flow and length Friction factor and diameter Friction loss and flow Length and diameter ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Meta-centric height is given as the distance between Center of buoyancy and metacenter The center of gravity of the body and the metacenter The center of gravity of the body and the center of pressure The center of gravity of the body and the center of buoyancy Center of buoyancy and metacenter The center of gravity of the body and the metacenter The center of gravity of the body and the center of pressure The center of gravity of the body and the center of buoyancy ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Euler's number is the ratio of __________ force to pressure force. None of these Inertia Viscous Gravity None of these Inertia Viscous Gravity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] ANSWER DOWNLOAD EXAMIANS APP
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