Engineering Mechanics Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point Thrice Four times Twice Same as Thrice Four times Twice Same as ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The range of a projectile is maximum, when the angle of projection is 60° 45° 30° 90° 60° 45° 30° 90° ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum acceleration of a particle moving with simple harmonic motion is ωr ω/r ω ω²r ωr ω/r ω ω²r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A smooth cylinder lying on its convex surface remains in __________ equilibrium. None of these Neutral Unstable Stable None of these Neutral Unstable Stable ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by (where, r = Amplitude of motion, and y = Displacement of the particle from mean position.) ω².√(y² - r²) ω.√(r² - y²) ω.√(y² - r²) ω².√(r² - y²) ω².√(y² - r²) ω.√(r² - y²) ω.√(y² - r²) ω².√(r² - y²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS