MGVCL Exam Paper (30-07-2021 Shift 3) Job, in operating system refers to Application Software System software Program Process Application Software System software Program Process ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Match the following shown in table A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) A = (iii), B = (ii), C = (i) A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) A = (iii), B = (ii), C = (i) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Bus Type - Known Parameter - Unknown ParameterLoad Bus -P, Q - V, phase angleGenerator Bus - P, V (magnitude) - Q, Voltage phase angleSlack Bus Voltage - magnitude and phase angle - P, Q
MGVCL Exam Paper (30-07-2021 Shift 3) નીચે પૈકી 'ઓસોડ' નો સમાનર્થી શબ્દ કયો છે? અમર અનરવું ઔષધ વૃંદા અમર અનરવું ઔષધ વૃંદા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) સારું:નરસું::શુક્લ: ? કૃષ્ણ અવિશાની અમર પરમ કૃષ્ણ અવિશાની અમર પરમ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A single phase motor connected to 400 V, 50 Hz supply takes 25 A at a power factor of 0.75 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.95 lagging. 92.55 pF 82.55 pF 72.55 pF 62.55 pF 92.55 pF 82.55 pF 72.55 pF 62.55 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For single phase induction motor,P = V*I*cosφ= 400*25*0.75= 7500 WQ1 = P*tan(φ) = 7500*0.80= 6015 VARNow power factor change to 0.95So, φ' = 25.84 degreeQ = 7500*tan(18.19)= 2464.424Qnet = Q - Q'= 6015 - 2464.424= 4500.8C = V²/(2*ᴨ*f*Q)= (400*400)/(2*ᴨ*50*3575.76)= 8.255*10^(-5)= 82.55 μF
MGVCL Exam Paper (30-07-2021 Shift 3) Name the application under MS Office software bundle, that we use to create audio- visual presentation. MS Access MS Word MS Power point MS Excel MS Access MS Word MS Power point MS Excel ANSWER DOWNLOAD EXAMIANS APP
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