Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
Fractions and Decimals [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] = ? 100 1000 100000 10000 100 1000 100000 10000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] Which is in form of [(a² + b² + c²)] /[ (a/10)² + (b/10)² + (c/10)²] = 100 x (a² + b² + c²) / (a²+b²+c²) = 100
Fractions and Decimals If √0.05 x 0.5 x a = 0.5 x 0.05 x √b, then a/b = ? .025 .0025 25 .00025 .025 .0025 25 .00025 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = √0.5 x .5 x a = .5 x .05 x √ b⇒ √.025 x a = 0.25 x ⇒ b⇒ 0.025a = 0.25 x .025 x b∴ a/b = (.025 x .025) /.025 = .025
Fractions and Decimals A person was asked to state his age in years. His reply was , "Take my age 3 years hence, multiply it by 3 and subtract 3 times my age 3 years ago and you will know how old I am." What was the age of 16 18 17 19 16 18 17 19 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the present age of person be x years.Then, 3(x + 3) - 3(x - 3 ) = x <=> (3x + 9) - (3x - 9) = x <=> x = 18
Fractions and Decimals Find the value of 1/3 + 1/15 + 1/35 + 1/63 + 1/99 . 7/11 5/11 10/11 9/11 7/11 5/11 10/11 9/11 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1/3 + 1/15 + 1/35 + 1/63 + 1/99= [1/3 + 1/15] + 1/35 + 1/63 + 1/99 = [6/15 + 1/35] + 1/63 + 1/99= 45/105 + 1/63 + 1/99 = [3/7 + 1/63] + 1/99= 28/63 + 1/99 = 4/9 + 1/99= 44 + 1/99 = 45/99 = 5/11
Fractions and Decimals 9.99 x 9.9 x 9 ÷ 9.9 ÷ 0.3 = ? 1.11 3.33 2.22 4.44 1.11 3.33 2.22 4.44 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = (9.99 x 9.9 x 9)/(9.9 x 0.9 x 0.3) = 3.33
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