In the circuit shown, find the equivalent resistance between A and B.<br/>

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, find the equivalent resistance between A and B.

75 ohm

150 ohm

100 ohm

50 ohm

75 ohm

150 ohm

100 ohm

50 ohm

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SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

5 Ω

1 Ω

10 Ω

2 Ω

5 Ω

1 Ω

10 Ω

2 Ω

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SSC JE Electrical 2019 with solution SET-1
The Norton’s current in the circuit shown below is

4A

120A

2A

12A

4A

120A

2A

12A

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SSC JE Electrical 2019 with solution SET-1
When the supply to the excitation fails, the synchronous generator acts like a/an

Induction motor

Induction generator

Synchronous generator

Synchronous motor

Induction motor

Induction generator

Synchronous generator

Synchronous motor

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SSC JE Electrical 2019 with solution SET-1
The Thevenin’s resistance as seen through the terminals A and B is:

5 Ω

8 Ω

6 Ω

4 Ω

5 Ω

8 Ω

6 Ω

4 Ω

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SSC JE Electrical 2019 with solution SET-1
P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is:

Meter per hour

Cubic meter per second

Meter per second

Square meter per second

Meter per hour

Cubic meter per second

Meter per second

Square meter per second

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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1 In the circuit shown, find the equivalent resistance between A and B.

SSC JE Electrical 2019 with solution SET-1 Please check out below figure.

SSC JE Electrical 2019 with solution SET-1 The Norton’s current in the circuit shown below is

SSC JE Electrical 2019 with solution SET-1 When the supply to the excitation fails, the synchronous generator acts like a/an

SSC JE Electrical 2019 with solution SET-1 The Thevenin’s resistance as seen through the terminals A and B is:

SSC JE Electrical 2019 with solution SET-1 P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is:

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, find the equivalent resistance between A and B.

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

SSC JE Electrical 2019 with solution SET-1
The Norton’s current in the circuit shown below is

SSC JE Electrical 2019 with solution SET-1
When the supply to the excitation fails, the synchronous generator acts like a/an

SSC JE Electrical 2019 with solution SET-1
The Thevenin’s resistance as seen through the terminals A and B is:

SSC JE Electrical 2019 with solution SET-1
P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is: