Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 700,400 820,369 800,500 820,360 700,400 820,369 800,500 820,360 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is: 64 124 260 156 64 124 260 156 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the numbers is 77,find the other. 99 79 109 89 99 79 109 89 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = 11 X 693 = 99 77
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 5 4 3 6 5 4 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case. 48 35 22 52 48 35 22 52 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62) = H.C.F. of 70, 105 and 175 = 35.
Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 88 55 77 66 88 55 77 66 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
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