RCC Structures Design In a singly reinforced beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete Plane sections transverse to the centre line of the beam before bending remain plane after bending Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 100 cm 50 cm 150 cm 200 cm 100 cm 50 cm 150 cm 200 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Cantilever retaining walls can safely be used for a height not more than 3 m 6 m 5 m 4 m 3 m 6 m 5 m 4 m ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The transverse reinforcements provided at right angles to the main reinforcement Resist the temperature stresses Resist the shrinkage stress Distribute the load All of these Resist the temperature stresses Resist the shrinkage stress Distribute the load All of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The neutral axis of a T-beam exists At the bottom edge of the slab Within the flange All listed here Below the slab At the bottom edge of the slab Within the flange All listed here Below the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² ANSWER DOWNLOAD EXAMIANS APP
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