RCC Structures Design If the ratio of the span to the overall depth does not exceed 10, the stiffness of the beam will ordinarily be satisfactory in case of a Cantilever beam Simply supported beam None of these Continuous beam Cantilever beam Simply supported beam None of these Continuous beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The maximum area of tension reinforcement in beams shall not exceed 4 % 0.15 % 6 1 4 % 0.15 % 6 1 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is f = (P/'+ (Z/M) f = (A/P) + (M/Z) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (P/'+ (Z/M) f = (A/P) + (M/Z) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The toe projection of foundation slabs is taken As one sixth of overall height of the wall Equal to heel slab Below ground surface As one third of the base As one sixth of overall height of the wall Equal to heel slab Below ground surface As one third of the base ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are effective lateral loadings at the bottom and top exerted by a level earth subjected to a super-load on the vertical face of height h of a retaining wall, the horizontal pressure p per unit length of the wall, is [(p₁ + p₂)/2] h [(p₁ + p₂)/4] h [(p₁ - p₂)/2] h (p₁ - p₂) ⅔h [(p₁ + p₂)/2] h [(p₁ + p₂)/4] h [(p₁ - p₂)/2] h (p₁ - p₂) ⅔h ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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