Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as -8.9 m/s2 +9.8 m/s2 +8.9 m/s2 -9.8 m/s2 -8.9 m/s2 +9.8 m/s2 +8.9 m/s2 -9.8 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act Zero at its upper end Downward at its upper end Perpendicular to the wall at its upper end Upward at its upper end Zero at its upper end Downward at its upper end Perpendicular to the wall at its upper end Upward at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics On the ladder resting on the ground and leaning against a smooth vertical wall, the force of friction will be Perpendicular to the wall at its upper end Zero at its upper end Upwards at its upper end Downwards at its upper end Perpendicular to the wall at its upper end Zero at its upper end Upwards at its upper end Downwards at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The horizontal range of a projectile (R) is given by R = u² cos2α/g R = u² sinα/g R = u² sin2α/g R = u² cosα/g R = u² cos2α/g R = u² sinα/g R = u² sin2α/g R = u² cosα/g ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The unit of angular velocity is Revolutions/min rad/s Both (B) and (C) m/min Revolutions/min rad/s Both (B) and (C) m/min ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα ANSWER DOWNLOAD EXAMIANS APP
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