Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(y² - r²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In a simple screw jack, the pitch of the screw is 9 mm and length of the handle operating the screw is 45 cm. The velocity ratio of the system is 1.5 314 25 5 1.5 314 25 5 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In SI units, the units of force and energy are respectively Dyne and erg kg wt and joule Newton and joule Newton and watt Dyne and erg kg wt and joule Newton and joule Newton and watt ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A projectile is fired with a velocity of 100.3 m/sec. at an elevation of 60°. The velocity attained by the projectile when it is moving at a height of 100 m, is 90 m/sec 80 m/sec 70 m/sec 75 m/sec 90 m/sec 80 m/sec 70 m/sec 75 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π - 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π + 0.5) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals P sin θ/P + Q tan θ Q sin θ/P + Q cos θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ ANSWER DOWNLOAD EXAMIANS APP
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