Engineering Mechanics If a number of coplanar forces acting at a point be in equilibrium, the sum of clockwise moments must be __________ the sum of anticlockwise moments, about any point. Equal to Greater than None of these Less than Equal to Greater than None of these Less than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A weight of 1000 N can be lifted by an effort of 80 N. If the velocity ratio is 20, the machine is None of these Ideal Reversible Non-reversible None of these Ideal Reversible Non-reversible ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a body of mass moment of inertia 'I' (about a given axis) is rotated about that axis with an angular velocity to, then the kinetic energy of rotation is 0.5 Iω2 0.5 Iω Iω Iω2 0.5 Iω2 0.5 Iω Iω Iω2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is _________ the momentum of body having mass m2. None of these Equal to Greater than Less than None of these Equal to Greater than Less than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Non-coplanar non-concurrent forces are those forces which None of these Do not meet at one point but their lines of action lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane Meet at one point, but their lines of action do not lie on the same plane None of these Do not meet at one point but their lines of action lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane Meet at one point, but their lines of action do not lie on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα ANSWER DOWNLOAD EXAMIANS APP
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