Power Systems If a 500 MVA, 11 kV 3-phase generator at 50 Hz feeds through a transfer impedance of (0+j0.605) Ω/phase, an infinite voltage also at 11 kV, then the maximum steady state power transfer on the base of 500 MVA and 11 kV is 0.8 pu 0.5 pu 1 pu 0.4 pu 0.8 pu 0.5 pu 1 pu 0.4 pu ANSWER DOWNLOAD EXAMIANS APP
Power Systems The per unit impedance Z(pu) is given by ZΩ* (kVA)b/(KV)²b ZΩ* (MVA)b/((KV)²b *100) ZΩ* (MVA)b/(KV)²b ZΩ* (MVA)b*100/(KV)²b ZΩ* (kVA)b/(KV)²b ZΩ* (MVA)b/((KV)²b *100) ZΩ* (MVA)b/(KV)²b ZΩ* (MVA)b*100/(KV)²b ANSWER DOWNLOAD EXAMIANS APP
Power Systems Suspension type insulators are used for voltage beyond 33 kV 440 V 230 V 11 kV 33 kV 440 V 230 V 11 kV ANSWER DOWNLOAD EXAMIANS APP
Power Systems The receiving end voltage for a long line under no load condition is any of the above less than the sending end voltage equal to the sending end voltage more than the sending end voltage any of the above less than the sending end voltage equal to the sending end voltage more than the sending end voltage ANSWER DOWNLOAD EXAMIANS APP
Power Systems The per unit impedance of a circuit element is 0.30. If the base kV and base MVA are halved, then the new value of the per unit impedance of the circuit element will be 0.0030 0.0060 0.60 0.30 0.0030 0.0060 0.60 0.30 ANSWER DOWNLOAD EXAMIANS APP
Power Systems An ACSR conductor has a diameter of 2 cm has internal inductance of 0.05 mH/Km. If this ACSR is replaced with another having a diameter of 4 cm then its internal inductance is 0.05 mH/Km 0.1 mH/Km 0.025 mH/Km 0 mH/Km 0.05 mH/Km 0.1 mH/Km 0.025 mH/Km 0 mH/Km ANSWER DOWNLOAD EXAMIANS APP
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