Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080
Time required for service before overhauling = 2/3h = 40 min in 45 days and time required for service after overhauling =2/3h= 40 min in 60 days Now,LCM of 45 and 60 = 180 days time required for service before overhauling is 180 days = 40 x 4 = 160 min and time required for service before overhauling is 180 days =40 x 3 = 120 min ∴ fraction of time saved = 160 - 120/160 =40/160 = 1/4
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