Problems on H.C.F and L.C.M HCF of 3/16, 5/12, 7/8 is: 5/48 2/47 3/47 1/48 5/48 2/47 3/47 1/48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 242 seconds 240 seconds 246 seconds 243 seconds 242 seconds 240 seconds 246 seconds 243 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of t 3 min 2 min None 1 min 3 min 2 min None 1 min ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 101 111 107 185 101 111 107 185 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7 m, 3 m 85 cm, 12 m 95 cm is : 35 cm 15 cm 25 cm 42 cm 35 cm 15 cm 25 cm 42 cm ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 17/29 11/13 31/45 23/37 17/29 11/13 31/45 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
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