Electric Circuits From the circuit diagram shown in question 1 find the Norton current. 1 A. 2.5 A. 4 A. 2 A. 1 A. 2.5 A. 4 A. 2 A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A series circuit consists of R = 20 Ω, L = 20 mH, and AC supply 60 V with f = 100 Hz. The voltage drop across L is 45.5 V. 39.1 V. 31.9 V. 50.5 V. 45.5 V. 39.1 V. 31.9 V. 50.5 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Two electric bulbs have transparent filament of same thickness. It one of them gives 60 W and other gives 100 W, then- 60 W lamp filament has longer length. 60 W lamp filament has shorter length. 60 W and 100 W lamp filament have equal length. 100 W lamp filament has longer length. 60 W lamp filament has longer length. 60 W lamp filament has shorter length. 60 W and 100 W lamp filament have equal length. 100 W lamp filament has longer length. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits When AC flows through a pure capacitance then the current is in phase with emf. leads the emf by - 90o. lags the emf by 90o. leads the emf by 90o. is in phase with emf. leads the emf by - 90o. lags the emf by 90o. leads the emf by 90o. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The electron is lighter than a proton by a factor of about 184. 18400. 1840. 18.4. 184. 18400. 1840. 18.4. ANSWER DOWNLOAD EXAMIANS APP
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