Electric Circuits For the resonance circuit ω0 = 105, Q = 50, R = 400 Ω the value of C is 500 pF. 1000 pF. 125 pF. 250 pF. 500 pF. 1000 pF. 125 pF. 250 pF. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Five cells are connected in series in a row and then four such rows are connected in parallel to Feed the current to a resistive load of 1.25Ω. Each cell has an emf of 1.5 V with internal resistance Of 0.2Ω. The current through the load will be 5 A 23.33 A 1 A 3.33 A 5 A 23.33 A 1 A 3.33 A ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} None of these i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} None of these ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Find the total power absorbed by the resistor in the given circuit. 12 W. 30 W. 24 W. 6 W. 12 W. 30 W. 24 W. 6 W. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Link in network theory refers to B - N - 1. B - N + 1. N - B - 1. N - 1. B - N - 1. B - N + 1. N - B - 1. N - 1. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In steady state condition capacitor acts as a open circuit voltage source current source short circuit open circuit voltage source current source short circuit ANSWER DOWNLOAD EXAMIANS APP
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