Surveying For mapping any country Primary triangles are broken down into secondary triangles of somewhat lesser accuracy All listed here Geodetic triangulation of greatest possible sides and accuracy is carried out Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys Primary triangles are broken down into secondary triangles of somewhat lesser accuracy All listed here Geodetic triangulation of greatest possible sides and accuracy is carried out Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys ANSWER DOWNLOAD EXAMIANS APP
Surveying The prime vertical passes through The east point of the horizon The zenith point of the observer The west point of the horizon All of these The east point of the horizon The zenith point of the observer The west point of the horizon All of these ANSWER DOWNLOAD EXAMIANS APP
Surveying The chord of a curve less than peg interval, is known as Sub-chord Small chord Short chord Normal chord Sub-chord Small chord Short chord Normal chord ANSWER DOWNLOAD EXAMIANS APP
Surveying If the reduced bearing of a line AB is N60°W and length is 100 m, then the latitude and departure respectively of the line AB will be +86.6 m, -50 m +70.7 m, -50 m +50 m, +86.6 m +50 m, -86.6 m +86.6 m, -50 m +70.7 m, -50 m +50 m, +86.6 m +50 m, -86.6 m ANSWER DOWNLOAD EXAMIANS APP
Surveying Which of the following errors can be eliminated by taking mean of bot face observations ? error due to line of collimation not being perpendicular to horizontal axis error due to eccentricity of verniers error due to imperfect graduations error due to imperfect adjustment of plate levels error due to line of collimation not being perpendicular to horizontal axis error due to eccentricity of verniers error due to imperfect graduations error due to imperfect adjustment of plate levels ANSWER DOWNLOAD EXAMIANS APP
Surveying When a star is between the pole and the horizon, the relationship between latitude (λ), zenith distance (z) and declination δ, is θ = δ - z θ = (z + δ) - 180° θ = z + δ θ = 180° - (z + δ) θ = δ - z θ = (z + δ) - 180° θ = z + δ θ = 180° - (z + δ) ANSWER DOWNLOAD EXAMIANS APP
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