Engineering Mechanics For a self locking machine, the efficiency must be 1 Less than 50% Equal to 50% Greater than 50% 1 Less than 50% Equal to 50% Greater than 50% ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio for the first system of pulleys is (where n is the number of pulleys.) 2n 2n - 1 n n² 2n 2n - 1 n n² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a first system of pulleys with 4 pulleys is 4 20 16 8 4 20 16 8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a rectangular section 3 cm wide and 4 cm deep about X-X axis is 16 cm4 9 cm4 12 cm4 20 cm4 16 cm4 9 cm4 12 cm4 20 cm4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum efficiency of a lifting machine is 1/m m/V.R. V.R./m 1/(m × V.R.) 1/m m/V.R. V.R./m 1/(m × V.R.) ANSWER DOWNLOAD EXAMIANS APP
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