Alligation or Mixture problems Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg. 3:4 1:3 2:3 4:5 3:4 1:3 2:3 4:5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP By the rule of alligation:Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind Required ratio = 60 : 90 = 2 : 3
Alligation or Mixture problems Three bottles of equal capacity have mixture of milk and water in ratio 5 : 7, 7 : 9 and 2 : 1 respectively. These three bottles are emptied into a large bottle. What is the percentage of milk in the new mixture? 51.2 49.6 52.3 50.7 51.2 49.6 52.3 50.7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let initial quantity be Q, and final quantity be F F = Q(1 - 8/Q) 4 => Q = 20
Alligation or Mixture problems There are three bottles of mixture of syrup and water of ratios 2:3, 3:4 and 7:5. 10 Litres of first and 21 Litres of second bottles are taken. How much quantity from third bottle is to be taken so that final mixture from three bottles will be of ratios 1:1. 35 Litres 25 Litres 30 Litres 20 Litres 35 Litres 25 Litres 30 Litres 20 Litres ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems In a mixture of 240 lt. water is 20% and rest is Milk. What quantity of mixture should be taken out and replaced with water so that water becomes 40%? 50 lit 60 lit 45 lit 55 lit 50 lit 60 lit 45 lit 55 lit ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, the profit %? 33.33% 22.5% 20% 25% 33.33% 22.5% 20% 25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP As water costs free, water sold at cost price of milk gives the profit. Required profit % = 5/20 x 100 = 5 x 5 = 25%.
Alligation or Mixture problems In a container, there is 960 ltr of pure milk from which 48 ltr of milk is replaced with 48 ltr of water, again 48 ltr milk is replaced by same amount of water, as this process is done once more. Now, what is the amount of pure milk? 823.08 ltr 901.54 ltr 719.64 ltr 821.54 ltr 823.08 ltr 901.54 ltr 719.64 ltr 821.54 ltr ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Amount of pure milk= a(1 ?b/a)n(n = 3, a = pure milk and b = amount replaced)= 960 (1 ?48/960)^3= 960(1-1/20)^3= 960 * 19/20 * 19/20*19/20= 823.08 lt.
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