Find the integer which when decreased by 2 is 80 times the reciprocal of the same number

• A. 10
• B. 13
• C. 11
• D. 12

Answer: (A)

Let the number be X Decreasing 2 from XX - 2 = 80 x (1/X)X^2 - 2X = 80X^2 -2x -80 = 0(X-10)(X+8) = 0x=10,-8X has two values, but among the given options X value should be 10