SSC JE Electrical 2018 with solution SET-1
Determine the current (in A) that flows through a 15 Ohms resistance, when the potential difference between the terminals of the resistors is 60 V
The phase angle θ of a series RL circuit is given as θ = tan−1(XL ⁄ R) Where XL = Inductive Reactance = 37.53 R = Resistance = 65 θ = tan−1(37.53 ⁄ 65) θ = tan−1(0.57) θ = 30°
EXAMIANS