Electric Circuits Consider the following circuit : Switch is closed at t = 0 Find i(0 +) V / {R + (sL + 1 / Cs)}. V/R. 0. (V*L) / (R*C) V / {R + (sL + 1 / Cs)}. V/R. 0. (V*L) / (R*C) ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A 230V, 50Hz voltage is applied to a coil having L = 5H and R = 2 Ohm in series with capacitance C. When the voltage across the coil is 400V, find the value of C? 10.54 µF. 1.8 µF. 8.51 µF. 4.78 µF. 10.54 µF. 1.8 µF. 8.51 µF. 4.78 µF. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The power dissipated in a pure capacitor is zero. proportional to applied voltage. both (B) and (C) above. proportional to the value of capacitance. zero. proportional to applied voltage. both (B) and (C) above. proportional to the value of capacitance. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits You have to replace 1500 Ω resistor in radio. You have no 1500 Ω resistor but have several 1000 Ω ones which you would connect two in parallel. three in parallel. two in parallel and one in series. three in series. two in parallel. three in parallel. two in parallel and one in series. three in series. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In the circuit given, I = 1 A for Is = 0. What is the value of I for Is = 2 A ? 1 A. 2 A. 4 A. 3 A. 1 A. 2 A. 4 A. 3 A. ANSWER DOWNLOAD EXAMIANS APP
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